Question

a train moving with uniform acceleration crosses station a with a velocity of 108 kilometre per hour and another station B with a velocity of 144 kilometre per hour .the time taken for the train to travel from A to B is 20 minutes . the distance between the two stations is ?

a)24km
B)42km
c)32km
d)40km

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Answer 1

Explanation:

Given:-

u=108km/ph

v=144km/ph

time(t)=20m=1/3hour

To find:-

distance

Solution:-

The formula is

$\large{\boxed{\frac{v-u}{t}}}$

$\implies{distance={\frac{144-108}{\frac{2}{3}}}}$

$={\frac{36}{\frac{2}{3}}}$

$={\frac{36×2}{3}}$

$={\frac{72}{3}}$

$={\boxed{24km}}$

Answer 2

Answer:

Kinetic energy, form of energy that an object or a particle has by reason of its motion. ... Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass.