A train moving with velocity of 54km/h is accelerated so that it's velocity becomes 72km/h in15 seconds find the acceleration of the train
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Hi there!
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Given :
Initial velocity (u) = 54 km/h = 15 m/s.
Final velocity (v) = 72 km/h = 20 m/s.
Time (t ) = 15 sec
To find :
Acceleration (a) = ?
Solution :
We will use first equation of motion ;
v = u + at
⇒ 20 = 15 + a × 15
⇒ 20 = 15 + 15a
⇒ 15a = 20 - 15
⇒ 15a = 5
⇒ a = 5/15
⇒ a = 0.33 m/s².
Hence,
The Acceleration is 0.33 m/s².
_______________________
Thanks for the question !
☺️☺️☺️
_______________________
Given :
Initial velocity (u) = 54 km/h = 15 m/s.
Final velocity (v) = 72 km/h = 20 m/s.
Time (t ) = 15 sec
To find :
Acceleration (a) = ?
Solution :
We will use first equation of motion ;
v = u + at
⇒ 20 = 15 + a × 15
⇒ 20 = 15 + 15a
⇒ 15a = 20 - 15
⇒ 15a = 5
⇒ a = 5/15
⇒ a = 0.33 m/s².
Hence,
The Acceleration is 0.33 m/s².
_______________________
Thanks for the question !
☺️☺️☺️
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