A train needs to reach its destination 1200 KM away in 18 hours. It starts at 60Km/hr and goes on for 7 hours. Due to an emergency, train stops and doesn't move for 1 hours and 30 minutes. Now, the train travels at 75 Km/hr for 5 hours. What must be the average speed of the train for the remaining journey, i it has to reach the destination at the exact expected time?
Answers
Answered by
0
Answer:
Correct option is
B
96 km /hr
Letthedistancebex,timetakentotravel=120x,timetakentoreturn=80x,averagespeed=timetakenTotaldistance=120x+80x2x=5x2x∗240=96km/hr
Answered by
1
Answer:
The train should travel at a speed of 90kmph.
Explanation:
The total distance is 1200km.
It went at 60kmph for 7 hours thus distance is 420 km.
Next it halted for 1.5 hours.
Then it travelled for 5 hours at 75 kmph thus distance is 5×75= 375.
total distance traveled is 420+ 375=795. Total time is 13.5 hours.
Thus train should travel 1200-795= 405 km in 18-13.5= 4.5 hrs
Thus it should travel at a speed of 405/45= 90kmph.
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