A train of length 100 m travelling at 20 m/s overtakes another of length 200 m travelling at 10 m/s . The time taken by the first train to pass the second train is ??
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So it's a kinematics problem.
Let T1 be the first train and T2 be the second train.
So, S1(length of T1) =100m ,S2=200m
V1=20m/s, V2=10m/s
V12(realtive velocity) = 20-10=10m/s.
S=100+200=300m
S=it+1/2at^2 but a=0
hence ,S=ut
300=10×t
=> t=30 sec
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Please mark it as brainliest if it was helpful :-):-)
So it's a kinematics problem.
Let T1 be the first train and T2 be the second train.
So, S1(length of T1) =100m ,S2=200m
V1=20m/s, V2=10m/s
V12(realtive velocity) = 20-10=10m/s.
S=100+200=300m
S=it+1/2at^2 but a=0
hence ,S=ut
300=10×t
=> t=30 sec
_______________________________________
Please mark it as brainliest if it was helpful :-):-)
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