A train of length 180 M is moving with a uniform speed crosses a telephone pole 18 seconds due to detachment of some coaches its length is reduced to 150 M now that time (seconds)taken by this train moving with same speed to cross a bridge of length 100m is
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l₁=180m
t₁=18 s
s= l₁/t₁
= 10 m/s
l₂= 150m
length of bridge(l₃) =100m
to cross a bridge of 100 m the train covers (d)=l₂+l₃
t₂= d/s
t₂=250/10
t₂=25 secs
t₁=18 s
s= l₁/t₁
= 10 m/s
l₂= 150m
length of bridge(l₃) =100m
to cross a bridge of 100 m the train covers (d)=l₂+l₃
t₂= d/s
t₂=250/10
t₂=25 secs
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