Question

A train of length 200 m travelling at 30 ms- over-
takes another train of length 300 m travelling at 20
ms-'. The time taken by the first train to pass the
second is
(a) 20 s
(b) 30s
(c) 40s
(d) 50 s​

Answer 1

Answer:

Step-by-step explanation:

Given :-

For the First Train,  

Length = 200 m.  

Speed = 30 m/s.  

For the Second train,

Length = 300 m.  

Speed = 20 m/s.  

To Find :-

Time taken by the first train to pass the  second Train.

Formula to be used :-

Time Taken = Distance/Time

Solution :-

Total distance :-

= (200 + 300) m

= 500 m .

Speed :-

= (30 - 20) m/s

= 10 m/s .

Time taken :-

= 500/10 s

= 50 seconds .

Hence, The time taken by the first train to pass the  second is 50 seconds.

Answer 2

• Length of first train (L1)= 200 m

• Length of second/another train (L2) = 300 m

• Speed of first train = 30 m/s

• Speed of another train = 20 m/s.

____________ [ GIVEN ]

• We have to find the time taken by the first train to pass the second train.

______________________________

Now..

Total distance = Distance of first train + Distance of another train

→ 200 + 300

→ 500 m

Also..

Total speed = Speed of second/another train - Speed of first train.

→ 30 - 20

→ 10 m/s

(Speeds are subtracted because both the trains pass each other.)

____________________________

We know that..

Total Time = Total Distance/Total Speed

Put the known values in above formula

→ Total time = 500/10

→ Total time = 50 sec

Option d) 50 sec

____________________________

After 50 sec the first train to pass the second train.

_________ [ ANSWER ]

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