Question

A train of length 500 m crosses an electric pole in 25 sec. the train crosses a platform traveling at the same speed in 49 sec. what is the length of the platform?

Answer 1

length of 1st train = 500m 
time = 25s
so ,length of train travelled in a sec =500/25=20m/s
length of 2nd train = 20*49 = 980 m

Answer 2

Answer:

480 m

Step-by-step explanation:

Length of train = 500 m

It crosses an electric pole in 25 sec

Speed = $\frac{Distance}{Time}$

Speed = $\frac{500}{25}$

Speed = $20m/s$

Let the length of the platform be x

Length of train = 500 m

Total length = 500+x

Time = 49 sec

Speed = $\frac{Distance}{Time}$

$20=\frac{500+x}{49}$

$20 \times 49=500+x$

$980-500=x$

$480=x$

Hence the length of the platform is 480 m