A train of mass 16,800 kg is pulled by its locomotive with a force of 10,000 N and is speed increases from 10 m/s to 12 m/s in a distance of 50 m. Calculate the resisting force assumed constant for that distance.
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Answer: The resistive force is 7392N.
Explanation:
Given: Mass of the train-16800 kg.
We know that force is,
Force=Mass*Acceleration
F =m*a------(1) Let's keep this aside for some time.
We have the mass, let us find the acceleration.
Given
Initial speed=10m/s=u.
Final speed=12m/s=v.
Distance=50m=s.
Using v²-u²=2as.
(12)²-(10)²=2a50
144-100=100a
a=44/100
a=0.44m/s.
Substituting a in (1)
F =16800*0.44
=7392 N.
Hope it helps you.
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