Question

A train of mass 2000 quintals is moved up an incline of 1 in 50 with an acceleration 2 m/s?. The force of friction is 0.5 N/quintal . Find magnitude of applied force . [Ans: 4.402 x 10​

Answer 1

Explanation:

Force of friction = 0·5 N per quintal f = 0·5 × 2000 = 1000 N m = 2000 quintals = 2000 × 100 kg sin θ = 1/50, a = 2 m/s2 In moving up an inclined plane, force required against gravity = mg sin θ = 39200 N And force required to produce acceleration = ma = 2000 × 100 × 2 = 40,0000 N Total force required = 1000 + 39,200 + 40,0000 = 440200 N.Read more on Sarthaks.com - https://www.sarthaks.com/405435/calculate-the-force-required-move-train-2000-quintal-incline-plane-with-acceleration-ms