A train of mass 'm' moves along a plane which makes an angle (theta) with horizontal with velocity v. The power developed by engine is
a.) mgv cos(theta)
b.) mgv sin(theta)
C.) mgv/{cos(theta)}
d.) mgv tan(theta)
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Explanation:
The velocity of the body t sec. after the beginning of the motion becomes
V
ˉ
=
u
ˉ
+
gt
ˉ
The power developed by the gravity
mg
ˉ
at that moment is
P
ins
=
mg
ˉ
.
v
ˉ
=m(
g
ˉ
.
V
0
ˉ
+g
2
t)
=mg(gt−v
0
sinα)
As
mg
ˉ
is a constant force, so the e\average power,
p
av
=
T
A
=
T
mg
ˉ
.Δ
r
ˉ
where Δ
r
ˉ
is the net displacement of the body during time of the flight
as
mg
ˉ
⊥Δ
r
ˉ
so p
av
=0
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