a train passe the teleghrap post which are placed 76 metres apart alongside a railway track at interval of 4 second at what rate is the train travelling km per hour
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time= 4sec distance= 76m then the speed =76/4
=19m/sec
in km /hr the speed will be (19×18/5)
=342/5km/hr
=68 2/5km/hr
=19m/sec
in km /hr the speed will be (19×18/5)
=342/5km/hr
=68 2/5km/hr
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4 secod me= 76m
1 secondme=19m
60 second me= 19×60=1140M
lekin= 1. 140kmperhour
1 secondme=19m
60 second me= 19×60=1140M
lekin= 1. 140kmperhour
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