Question

A train passes a bridge 220m long in 30 secs and a station 325 m long in 39 secs. Find the length of the train and also it's speed ​

Answer 1

Answer:

Given s = t + 220/30 ... (i)

   and s =  t + 325/39 ... (ii)

Solving (i) and (ii), we get

39(t + 220) = 30(t + 325)

39t + 8580 = 30t + 9750

9t = 1170

t = 130 m

Put in (i), we get

Speed = 130 + 220/30

            = 350/30

            = 11.66 m/sec

S = 3600 × 11.66/1000

Step-by-step explanation: