A train passes a standing man in 3 seconds and a platform 105 m long in 8 seconds. Find the length of the train and its speed.
Answers
Answered by
3
Answer :-
v = 21 m/s
l = 63 m
Explanation :-
To pass the standing man, train travels the distance equal to its length.
l = v × t
l = 3v
To pass the platform, train travels the distance equal to its length plus platform.
l + 105 = v × t'
l + 105 = 8v
Putting l = 3v,
3v + 105 = 8v
5v = 105
v = 105 / 5
v = 21 m/s
To calculate l,
l = 3v
l = 3 × 21
l = 63 m
Therefore, length of the train is 63 m and velocity is 21 m/s.
Thanks ...
Answered by
2
Answer:
21m/s
Explanation:
see 105 m distance train will cover in 5 seconds coz in 3 seconds it will cover the distance of train length ...so 105/5=21m/s
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