Question

A train passes two bridge lengths 210m and 122m in 25sec and 17sec respectively. let's find the length and speed of the train ​

Answer 1

Step-by-step explanation:

We assume the train's length is x

the train covers a total distance of 210+x and 122+x

(210+x)/25=(122+x)/17 = speed of the train

-> (210+x)*17=(122+x)*25

-> 210*17+17x=122*25+25x

-> (210*17) - (122*25) = 8x

-> x= 65

So the length of the train is 65m

The speed of the train = (210+65)/25 or (122+65)/17 =11m/sec