Math, asked by as1037728, 1 month ago

a train passes two bridges of length 210m and 122m in 25sec and 17 sec respectively.let us calculated the length and speed of the train​

Answers

Answered by gamerharshit981
3

Step-by-step explanation:

Well assume the train's length is x. We also know that the speed of the train is the same when it's crossing both the bridges. In order to completely cross a bridge, the train has to cover the length of the bridge as well it's own length. So in either cases the train covers a total distance of 210+x and 122+x . Since the speed is the same, we can say:

-> (210+x)/25=(122+x)/17 = speed of the train

-> (210+x)*17=(122+x)*25

-> 210*17+17x=122*25+25x

-> (210*17) - (122*25) = 8x

-> x= 65

So the length of the train is 65m

The speed of the train = (210+65)/25 or (122+65)/17 =11m/sec

Answered by bhoomika1979
1

Well assume the train's length is x. We also know that the speed of the train is the same when it's crossing both the bridges. In order to completely cross a bridge, the train has to cover the length of the bridge as well it's own length. So in either cases the train covers a total distance of 210+x and 122+x . Since the speed is the same, we can say:

-> (210+x)/25=(122+x)/17 = speed of the train

-> (210+x)*17=(122+x)*25

-> 210*17+17x=122*25+25x

-> (210*17) - (122*25) = 8x

-> x= 65

So the length of the train is 65m

The speed of the train = (210+65)/25 or (122+65)/17 =11m/sec

Step-by-step explanation:

I hope it helps pls

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