Question

A train reaches a bridge PQ. Inside the tunnel is a dog located at a point that is 3/8 of the distance PQ measured from the entrance P. When the train beep the dog runs. If the dog moves to the entrance of the bridge P, the train catches the dog exactly at the entrance. If the dog moves to the exit Q, the train catches the dog at exactly the exit. If the speed of train is 40kmph then find the speed of the dog?

Answer 1

Answer:

10 kmph

Step-by-step explanation:

Let the train be at a distance y from A. Let the length of the tunnel AB be 8x. Therefore, the dog is at 3x from A.

Now both the conditions given in the questions assume same time scenario. Therefore, the ratio of the speeds of

the dog and the train will be equal to the ratio of the distances traveled by them.

Required ratio,

= > y/3x = (y +8x)/5x

=> y = 12.

Therefore, ratio of the speed = y/3x = 12x/3x = 4 : 1.

Given speed of train 40kmph

Applying the ration then we get the speed of dog as 10kmph

Answer 2

Answer:

Step-by-step explanation: