Question

A train requires 7 seconds to pass a pole while it requires 25 seconds to cross a stationary train which is 378 metres long. Find the speed of the train.

Answer 1

Answer:

=75.6 kmph

Explanation:

In 7s the train crosses the pole and in 25 sec the train crosses one more stationary train

In 18 sec the train travels a distance of 378 mtrs

Speed = 378/18 = 21 m/s = 21 (3600/1000) = 21 * 18/5 = 75.6 kmph

Answer 2

The speed of the train is 21 m/s.

Explanation:

The length of stationary train is 378 m.

Let the speed of the train is v.

As train crossed the pole is 7 sec.

And its takes the time to crossed the stationary train is 25 s.

That means it takes times 25-7 = 18 s to crossed another train which is 378 m long.

Therefore, the speed of the train is given as

v = distance /times

$v=\frac{378m}{18s}$

Thus, the speed of the train is 21 m/s.

#Learn More: speed.

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