Question

A train running at 2/5 of its own speed reached a place in 15hours . In what time could it reach there running at its own speed?

Answer 1

Answer:

2/5=15

5=7.5*5

888680558

Answer 2

Let the distance travelled be d and original speed of train be x km/hr.

New speed = 2x/5 km/hr

Distance = d

Time taken = d/t

=> 15 = d/(2x/5)

=> 15 = 5d/2x

=> x = 5d/(2*15)

.•. x = d/6

Time taken by train while running in its original speed = d/x = d/(d/6) = 6 hours

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