a train running at 4/7 ofbits own speed reached a place in 14 hours. in what time could it reach there running at its own speed?
Answers
Step-by-step explanation:
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Answer:
Answer:8 hours
Answer:8 hoursStep-by-step explanation:
Answer:8 hoursStep-by-step explanation:Let usual speed =x
Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7x
Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.
Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.Time=7/4x
Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.Time=7/4x7/4x=14
Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.Time=7/4x7/4x=14Therefore,
Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.Time=7/4x7/4x=14Therefore,x=8 ans