Math, asked by yusuff3, 5 months ago

a train running at 4/7 ofbits own speed reached a place in 14 hours. in what time could it reach there running at its own speed?​

Answers

Answered by karunajoshi205
2

Step-by-step explanation:

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Answered by babitachoudhary00260
3

Answer:

Answer:8 hours

Answer:8 hoursStep-by-step explanation:

Answer:8 hoursStep-by-step explanation:Let usual speed =x

Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7x

Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.

Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.Time=7/4x

Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.Time=7/4x7/4x=14

Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.Time=7/4x7/4x=14Therefore,

Answer:8 hoursStep-by-step explanation:Let usual speed =xNew speed=4/7xtime is proportion of speed.Time=7/4x7/4x=14Therefore,x=8 ans

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