Question

A train running at 7/11 of its own speed reached a place in 22 hrs. how much time can be saved if train would run at its own speed ?

Answer 1

Solution :-

The train ran at less than its full speed, which means it ran at a fraction of its full speed. This fraction is 7/11. 

So, according to the question.

New speed = 7/11th of the usual speed

Then, new time = 11/7 of the usual time

So, 11/7 of usual time = 22 hours

Usual time = (22*7)/11

= 154/11

= 14 hours

Usual time is 14 hours and the time taken at less speed is 22 hours.

Hence, Time can be saved if the train would run at its usual speed 

⇒ 22 - 14 = 8 hours.

Answer.

Answer 2

8 hours

Guess the train speed is x kmph

So, at 7/11 speed of x is the train goes 7x/11*22=14x km

Now,

the train goes 14x km at 7x/11 kmph in        22 hrs

the train could go 14x km at x kmph in       22*7x/11x = 14 hrs

It would have save 22 - 14 = 8 hours