Question

.A train running at 7/11 of its own speed reached a placein 33 hrs. How much time could be saved if the trainruns at its own speed?
1 point​

Answer 1

Answer:

8 hours

Step-by-step explanation:

The train ran at less than its full speed, which means it ran at a fraction of its full speed. This fraction is 7/11.

So, according to the question.

New speed = 7/11th of the usual speed

Then, new time = 11/7 of the usual time

So, 11/7 of usual time 22 hours

Usual time = (22*7)/11

= 154/11

= 14 hours

Usual time is 14 hours and the time taken at less speed is 22 hours.

Hence, Time can be saved if the train would run at its usual speed

→ 22 - 14 = 8 hours.

Answer 2

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Let its own speed be x

• Speed of the train = 7x/11
• Time to reach the place = 33 hrs

So, Distance = speed of the train × Time to reach the place

= (7x/11) × 33

= 21x unit.

Now , The own speed of the train= x

and distance = 21x unit.

so, time = distance/speed

= 21x/ x

= 21 hrs

So, the time could be saved (33-21)hrs = 12hrs

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