Question

A train running at (7/11)th of its speed reached a place in 22 hours. How much time could be saved if the train would have run at its speed?

explain it step by step
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Answer 1

the distance travelled by the train in 7/11th of its speed= speed×time.

let the total speed is x, then the current speed is 7x/11.

d= 7x/11×22

so distance is7x×2hours= 14x

when speed is x, the t= d÷s

= 14x÷x= 14 hours. so the train will take 14 hours

Answer 2

Answer:

Step-by-step explanation:

CASE I:

when train is running at 7/11th speed

let its original speed be v

therefore speed in this case would be=7v/11

let distance travelled be d

time taken to travel d distance= 22hrs

       speed=distance/time

       7v/11 = d / 22

       d/v = 14 ------------------------(1)

CASE 2:

now train is running at its original speed ie v

distance travelled is same =d

let time in this case be T

so,

     speed = distance / time

         v = d / T

         T= d / v

         T= 14                 (from equation (1) )

         T= 14 hours