Question

A train running at a speed of 120 kmph is approaching a station. Driver applies brakes just 200 m before
the station to stop it at the station. Find the retardation of the train.



Please explain quick

Answer 1

Answer:

Explanation:

initial velocity u=120*5/18 m/s= 100/3 m/s,s=200m,final velocity v=0,acceleration a=?

by using v^2-u^2=2as

0-10000/9=2*a*200

a= -2.77m/s^2

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Answer 2

Answer-:

11.11m/s^2

Explanation-:

apply V^2-u^2=2as

now v=0 ( because the train stops )

u=200/3 m/s ( convert 120 km/hr into m/s )

a= -ve ( retardation is negative acceleration )

by V^2-U^2= 2.-a.s

0-40000/9=2.-a.200

-40000/9=-400a

a= 11.11m/s^2