Question

a train running at the of speed 60 km/hr crosses a pole in 9 Seconds.what is the length of the train ?

Answer 1

speed of train in meter per second= 60*5/18=50/3mpersec
so, in 9 second train will go, d=s*t
=50/3 *9
= 150 metres

Answer 2

Answer:

Step-by-step explanation:

ANSWER:-

Given that:-

A train running at a speed of 84 km/h

The train crosses a electric pole at 9 seconds

We need to find the length of the train.

Let's Do!

What we can do here, is first convert the given units into SI units.

84 km/h => m/s

1 metre = 1000 km

1 hour = 3600 seconds

$\sf{Kmph = \dfrac{1000}{3600} = \dfrac{5}{18} \ After \ simplification}$

So, we can now multiply 84 with 5/18

It was just a shortcut method, you can use it directly as well.

So, we get:-

$\sf{\dfrac{84 \times 5}{18}}$

$\sf{ = 23.33 \ mps \ approximately}$

mps means metre/second.

Now, we know that

$\boxed{\sf{Speed = \dfrac{Distance}{Time} }}$

$\boxed{\sf{\mapsto Distance = Speed \times Time}}$

Now, we need is length ie Distance.

So, 23.33*9 = 209.97 metres is the length of the train.

Answer 3

Answer:

Step-by-step explanation:

ANSWER:-

Given that:-

A train running at a speed of 84 km/h

The train crosses a electric pole at 9 seconds

We need to find the length of the train.

Let's Do!

What we can do here, is first convert the given units into SI units.

84 km/h => m/s

1 metre = 1000 km

1 hour = 3600 seconds

$\sf{Kmph = \dfrac{1000}{3600} = \dfrac{5}{18} \ After \ simplification}$

So, we can now multiply 84 with 5/18

It was just a shortcut method, you can use it directly as well.

So, we get:-

$\sf{\dfrac{84 \times 5}{18}}$

$\sf{ = 23.33 \ mps \ approximately}$

mps means metre/second.

Now, we know that

$\boxed{\sf{Speed = \dfrac{Distance}{Time} }}$

$\boxed{\sf{\mapsto Distance = Speed \times Time}}$

Now, we need is length ie Distance.

So, 23.33*9 = 209.97 metres is the length of the train.