Question

A train runs a distance at a uniform speed, If the speed is 6 KPH more, the would have reached the destination 4 hour ahead. If the speed is 6 KPH less it would have taken another 6 hour. Find the speed of the train and the distance covered ​

Answer 1

Answer:

Train existing speed=x

Train will cover distance=y

First statement if speed increased by 10 km per hour then distance covered in 2 hours. Distance= speed ×time

(X+10)(t-2)=Y

And second statement if speed decreased by 10 km per hour them distance covered in 03 hours

(X-10)(t+3)=Y

Xt=Y

So (X+10)(t-2)=Xt

(X-10)(t+3)=Xt

Xt-2X+10t-20=Xt

10t-2X=20………(1)

And Xt+3X-10t-30=Xt

3X-10t=30………(2)

By 1 and 2

X=50 km ……..(3)

By 1 and 3

10t-100=20

t= 12 hours

Distance=speed × scheduled time

Distance= 50×12

Distance= 600 kms.