A train runs at a speed of 42 M/S and takes 35 seconds lo pass a tunnel. After travelling some distance, it takes 15 seconds to pass a pole. What is the length of the tunnel?
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3
the llength of train must be 2100 m
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While passing the tunnel it takes 35sec
Displacement = Velocity × Time
Therefore,
L(Train) + L(Tunnel)
= 42 × 35 = 1470m
Now,
It takes 15 sec to pass a pole
So,
L(Train)
= 15×42= 630m
L(Tunnel) = 1470 - 630 = 840
So,
The length of tunnel is 840m
Displacement = Velocity × Time
Therefore,
L(Train) + L(Tunnel)
= 42 × 35 = 1470m
Now,
It takes 15 sec to pass a pole
So,
L(Train)
= 15×42= 630m
L(Tunnel) = 1470 - 630 = 840
So,
The length of tunnel is 840m
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