Math, asked by yashasgbthaswika, 7 hours ago

A train runs (x² + 2x² -15) in (x² - 3 ) . Find the speed of the train in km/hour​

Answers

Answered by shaniaugustine8
1

Step-by-step explanation:

  • distance =  {x}^{2}  + 2 {x}^{2}  - 15
  • time =  {x}^{2}  - 3
  • speed \:  =  \frac{distance}{time}
  •  =  \frac{ {x}^{2} + 2 {x}^{2}   - 15 }{ {x}^{2}  - 3}
  •  = (2 {x}^{2}  - 5)km \: per \: hour
Answered by InvincibleAtharva
1

Answer:

Here's your answer.

Step-by-step explanation:

speed = distance/ time

speed = (x² + 2x² -15) / (x² - 3 )

speed = 3 - 6 / x^2 -3

Therefore speed of train = 3 - 6/x^2-3

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