Question

a train slowed down from 50 km h to 10 km h in 2 minutes how far did it travel in this time​

Answer 1

Answer:

u=50km/h

v=10km/h

t=2min=2/60=1/30hr

speed=distance/time

distance=speed×time

change in speed=50-10=40

distance=40×1/30

=4/3

=1.3km

Answer 2

Step-by-step explanation:

here,

u=50km/hr=5/6 Km per min

v=10km/hr

=1/6 km per min

t= 2 min

using v=u+at

1/6=5/6+a×2

-4/6=2a

a= -1/3 km/min^2

Now using s=ut+1/2 × at^2

s=5/6 × 2 + 1/2 ×-1/3 ×2×2

s=5/3 +(-2/3)

s=1km= 1000m=10^3m answer..............