Question

A train speeding at 120 km/hr crosses an electriv pole in 9 seconds and a platform in 24 seconds. What is the length of the platform ?​

Answer 1

Answer:

$\huge\underline\bold {Answer:}$

Speed of train = 120km/hr

$= 120 \times \frac{5}{18} \frac{m}{s}$

$= \frac{100}{3} \frac{m}{s}$

Time taken to cross the electric pole = 9 sec

Therefore, length of the train

$= \frac{100}{3} \times 9$

$= 300 \: m$

Let the length of the platform be x m.

Then a distance of (x + 300) m is to be covered in 24 seconds at a speed of 100/3 m/s.

Therefore

$(x + 300) = ( \frac{100}{3} \times 24) \: m$

=> x + 300 = 800

=> x = 500 m.

Answer 2

Step-by-step explanation:

Speed of train =120km/hr=120×185m/s=3100m/s

Time taken to cross the electric pole = 9 sec

∴ Length of the train =(3100×9)m=300m

Let the length of the platform be x m.

Then a distance of (x + 300) m is to be covered in 24 seconds at speed of 3100m/s

∴(x+300)=(3100×24)m

⇒x+300=800

⇒x=500m