Math, asked by aakash252535, 7 months ago

A train speeding at 120 km/hr crosses an electriv pole in 9 seconds and a platform in 24 seconds. What is the length of the platform ?​

Answers

Answered by Anonymous
2

Answer:

\huge\underline\bold {Answer:}

Speed of train = 120km/hr

 = 120 \times  \frac{5}{18}  \frac{m}{s}

 = \frac{100}{3}  \frac{m}{s}

Time taken to cross the electric pole = 9 sec

Therefore, length of the train

 =  \frac{100}{3}  \times 9

 = 300 \: m

Let the length of the platform be x m.

Then a distance of (x + 300) m is to be covered in 24 seconds at a speed of 100/3 m/s.

Therefore

(x + 300) = ( \frac{100}{3}  \times 24) \: m

=> x + 300 = 800

=> x = 500 m.

Answered by singhbhavya037
2

Answer:

Step-by-step explanation:

Speed of train =120km/hr=120×  

18 /5 m/s=  

3 /100 m/s

Time taken to cross the electric pole = 9 sec

∴ Length of the train =(  3 /100 ×9)m=300m

Let the length of the platform be x m.

Then a distance of (x + 300) m is to be covered in 24 seconds at speed of  

3  /100 m/s

∴(x+300)=(  3 /100 ×24)m

⇒x+300=800

⇒x=500m

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