Question

A train starding from rest attains a velocity of 72km/h in 5 min. Assuming the accelaration is uniform
find
a) acceleration
b) distance travelled by train for attaining this velocity​

Answer 1

Answer:

Here

u=0

v=72km/h

t=5min=300sec

1》We know that,

a= v-u/t

=72/300

=0.24m/sec^2

2》By Newton Second Law of Motion,

s=ut+1/2at^2

=0+1/2×18/75×(300)^2

=10800m

Explanation:

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