Question

A train staring from
rest
accelerates uniformly
and
attains a velocity 48 kmh-1 in
2 minutes. It travels at this
speed for 5 minutes. Finally, it
moves with uniform retardation
and is stopped after 3 minutes.
Find the total distance travelled
by the train.
(6000 m)​

Answer 1

Answer:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

Explanation:

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