a train staring from rest attains a velocity 72km/hr in 5min asuming that the acceleration is uniform find the acceleration and the distance attend by the train
shailsejal:
i guess the acceleration is -2/3
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the distance may be 12
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as the train is starting from the rest so here initial velocity of the train would be zero. The train then atains a velocity of 72km/hr i.e 20 m/s in 5min so time is 300 sec. so using the formula v=u+at we can find theacceleration and then by s=ut+1/2at^2 the distance.
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