Physics, asked by ArthGupta9359, 4 months ago

A train Start from one station reaches second station in 3 hr which is at 48 km away from first
station. And then returns back to the first station and takes 5 hr. Find the Average speed and average
velocity of the train​

Answers

Answered by Yuseong
4

Explanation:

As per the provided information in the given question, we have :

  • Time taken by train from one station (Station 1) to second station (Station 2) = 3 hrs

  • Time taken by train from second station (Station 2) to one station (Station 1) = 5 hrs

  • Distance between station one and second station = 48 km

We are asked to calculate average speed and average velocity of the train.

★ Calculating average speed of the train :

Average speed refers to the total distance covered divided by total time.

 \\ \longrightarrow \quad \pmb{\boxed{\sf {Speed_{(avg)} = \dfrac{Total \; distance}{Total \; time }}}}\\

 \\ \longrightarrow \sf{\quad Speed_{(avg)} = \dfrac{Distance_{(Station \; 1 \; to \; 2)} + Distance_{(Station \; 2 \; to \; 1) }}{Time_{(Station \; 1 \; to \; 2)} +Time_{(Station \; 2 \; to \; 1)}} } \\

 \\ \longrightarrow \sf{\quad {Speed_{(avg)} = \dfrac{(48 + 48) \; km }{(3 + 5) \; hrs} }} \\

 \\ \longrightarrow \sf{\quad {Speed_{(avg)} =\cancel{ \dfrac{ 96 \; km }{ 8\; hrs}} }} \\

 \\ \longrightarrow \bf{\quad {\underline{ Speed_{(avg)} = 12 \; km/h}}} \\

Therefore, average speed of the train is 12 km/h.

Calculating average velocity :

Average velocity refers to the total displacement divided by total time.

 \\ \longrightarrow \quad \pmb{\boxed{\sf {Velocity_{(avg)} = \dfrac{Total \; displacement}{Total \; time }}}}\\

The train came back to its initial position after covering certain distance. Whenever tha body comes back to its initial position after covering certain distance, then its displacement is 0.

 \\ \longrightarrow \sf{\quad {Velocity_{(avg)} = \dfrac{0\; km }{ (3 + 5) \; hrs} }} \\

 \\ \longrightarrow \sf{\quad {Velocity_{(avg)} =\cancel{ \dfrac{ 0 \; km }{ 8\; hrs}} }} \\

 \\ \longrightarrow \bf{\quad {\underline{ Velocity_{(avg)} = 0 \; km/h}}} \\

Therefore, average velocity of the train is 0 km/h.

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