Question

a train start from rest moves with uniform acceleration of 0.2m /s sq for 5 min calculate speed and distance travelled

Answer 1

distance = 9km and speed 1.8 km/ min

Answer 2

Initial velocity = 0 (u)

Acceleration (a) = 0.2 m/s

Time = 5 minutes..... = 60×5 = 300seconds


We know the formula of equation of motion :-

I.e v = u + at
v = 0 + 0.2 × 300 = 60m/s - speed

Distance traveletravelled= speed× time = 60×300=18, 000 m or 18km

Hope it helps

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