Question

a train start from rest moves with uniform accleration 0.2m/s sqa​

Answer 1

Answer:

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Step-by-step explanation:

INITIAL SPEED

= 0

TIME TAKEN : 5 min = 300 secs

FINAL SPEED

= v

then use kinematics equation

v = u + at

v = 0+0.2×300

= 60 m/s

DISTANCE TRAVELED

= s ( let )

USE FORMULA :

s = ut + 1/2 at^2

= 0+1/2×0.2×300^2

= 0.1 × 90000

= 9000 m

= 90 km