Question

A train started from station X was arrived at station Y at 6 pm. It could travel at 62.5%of its usual speed and reach Y at 7 pm. At what time train starts at X

Answer 1

Answer:

Let it started from station X at the spped for 100.

Time Of reaching at Y=6:06

Now then, speed is 62.5% I.e. 62.5

Time of reaching at Y=7:00

Let depart time be t

Then for 7:00 it will be t+54

Equating 2 situation:

100×t=62.5×(t+54)

it gives t=90

so it will be start 90 mins earlier then 6:06 PM

Hence Answer=4:36

Step-by-step explanation:

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