Question

A train starting at rest a home a velocity of 72 km/h in 5 minutes find the acceleration and the distance travelled by the train for attaining this velocity​

Answer 1

Answer:

u=0m/s

v=72km/h

t=5min

5×60=300seconds

a=(v-u)/t

=(72-0)/300

a=0.24m/s^2

s=ut+1/2at^2

s=0×300+1/2×0.24×300×300

s=0+10800

s=10800

therefore the train will travel 10.8km