Question

a train starting from a railway station and moving with uniform accelaration attains a speed 40km/h in 10minutes. find its acceleration​

Answer 1

Answer:

acceleration of the train

= 0.185 m/s²

Step by step explanations :

Given that,

a train starting from a railway station and moving with uniform accelaration attains a speed 40km/h

here,

initial velocity of the train = 0 m/s [It was initially at rest]

final velocity = 40 km/h

= 40 × 1000/3600 m/s

= 100/9 m/s

and time taken to reach the speed

= 10 minutes

= 600 s

now we have,

initial velocity(u) = 0 m/s

final velocity(v) = 100/9 m/s

time taken(t) = 600 s

so acceleration(a) = (v - u) /t

putting the values,

a = (100/9)/600

a = 100/5400

a = 0.185 m/s²

so,

acceleration of the train

= 0.185 m/s²

Answer 2

Answer

0.185 m/s2

As Per Given

u=0 km/hr.

v= 40 km/hr.

t = 10 min. = 1/6 hr.

Solution:-

According to 1st equation of motion

$v = u + at \\ 40 = 0 + \frac{1}{6} \times a \\ 40 = \frac{a}{6} \\ a = 240 \: km \: hr {}^{ - 2} \\ \\ in \: order \: to \: convert \: in \: m {s}^{ - 2} \\ \\ a </em><em>= </em><em>0.18</em><em>5</em><em> \: m {s}^{ - 2}$