A train starting from a railway station and moving with uniform acceleration attain a speed 40 km h-1 in 10 minutes. Find its acceleration.
Answers
Answered by
2
u=0m/s
v=40km/h=40*5/18=11.1m/s
t=10min*60=600sec
a=v-u/t
=11.1-0/600=0.0185m/s2
therefore acceleration =0,0185m/s2
hope it helped you
pls follow me and Mark me as brainliest
Answered by
1
Given:-
- Initial velocity of Train (u) = 0m/s
- Final velocity (v) = 40 km/h
- Time (t) = 10 min
To Find :-
- What is the acceleration of train ???
Solution :-
Firstly we can convert km/hr into m/s
⇒ 1 km/hr = 5/18
⇒ v = 11.11 m/s
Now, we can convert min into sec
⇒ 1 min = 60 sec
⇒ 60×10 = 600 sec
⇒ t = 600 sec
By using first equation of motion
- v = u + at
where,
Initial velocity = " u "
Final velocity = " v "
Time = " t "
acceleration = " a "
Now, putting the values in the above formula , we get
⇒ 11.1 = 0 + a × 600s
⇒ 11.1 = a × 600
⇒ a = 111/6000
⇒ a = 0.0185 m/s²
therefore,
The acceleration of the train is 0.0185 m/s².
_____________________
Similar questions