Question

A train starting from a railway station and moving with uniform acceleration attains a speed of 40 km/h in 10 minutes. Find its acceleration.

Answer 1

Answer:

Explanation

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.

Final speed of the train, v = 40 km/h = × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ a=v-u/t

Solution:-

Putting all the values, we get

0.0185..

Hence, Acceleration of the train is 0.0185 m/s².

Hope it helps..

Answer 2

Answer:

Know terms u = initial speed

v = final speed

a = acceleration

t = time

Given

initial speed of the train u = 0 km ( because train starts from the rest )

final speed of the train v =, 40 km / h

= 5/18× 40 = 11.11 m /s

Time taken to attain the speed = 10 min = 10 × 60 = 600 sec

To calculate Acceleration of the Train

Formula to be used = a = v - u / t

Solution

putting all the values

= a = v - u / t

a = 11.11 - 0 /600

a = 0.0185 m/s square

Hence , Acceleration of the train is 0.0185 m/s square

Explanation:

I hope this answer helps u