Question

a train starting from a railway station and moving with uniform acceleration attains a speed 40 km hour-¹ in 10 minutes.find its acceleration.​

Answer 1

Answer:

a = 0.0185.. m/s^2

Explanation:

Given :

Initial velocity = u = 0 m/s

Time = t = 10 minutes

1 minute = 60 seconds

10 minutes = 10×60= 600 seconds

Final velocity = v = 40 km/h

40 km/h = 40 × 5/18

40 km/h = 100/9 m/s

To find:

Acceleration (a)

Using the first equation of motion which says that : v=u+at

Substituting the values,:

100/9 = 0+a×600

100/9=600a

a = 100/9 × 1/600

a = 1/54 m/s^2

a = 0.0185.. m/s^2

The acceleration of the train is equal to 0.0185.. m/s^2

Answer 2

Answer:

Explanation:

Given :-

Initial velocity, u = 0 (As train starts from rest)

Final velocity, v = 40 km/h = 40 × 5/18 = 100/9 = 11.11 m/s

Time taken, t = 1 min = 10 × 60 = 600 seconds

To Find :-

Acceleration, a = ??

Formula to be used :-

1st equation of motion,

i.e, v = u + at

Solution :-

Putting all the values, we get

v = u + at

⇒ 11.11 = 0 + a × 600

⇒ a = 11.11 - 0/600

⇒ a = 11.11/600

⇒ a = 0.0185 m/s²

Hence, the acceleration by train is 0.0185 m/s².