a train starting from a railway station and moving with uniform acceleration attains a speed 40 km hour-¹ in 10 minutes.find its acceleration.
Answers
Answer:
a = 0.0185.. m/s^2
Explanation:
Given :
Initial velocity = u = 0 m/s
Time = t = 10 minutes
1 minute = 60 seconds
10 minutes = 10×60= 600 seconds
Final velocity = v = 40 km/h
40 km/h = 40 × 5/18
40 km/h = 100/9 m/s
To find:
Acceleration (a)
Using the first equation of motion which says that : v=u+at
Substituting the values,:
100/9 = 0+a×600
100/9=600a
a = 100/9 × 1/600
a = 1/54 m/s^2
a = 0.0185.. m/s^2
The acceleration of the train is equal to 0.0185.. m/s^2
Answer:
Explanation:
Given :-
Initial velocity, u = 0 (As train starts from rest)
Final velocity, v = 40 km/h = 40 × 5/18 = 100/9 = 11.11 m/s
Time taken, t = 1 min = 10 × 60 = 600 seconds
To Find :-
Acceleration, a = ??
Formula to be used :-
1st equation of motion,
i.e, v = u + at
Solution :-
Putting all the values, we get
v = u + at
⇒ 11.11 = 0 + a × 600
⇒ a = 11.11 - 0/600
⇒ a = 11.11/600
⇒ a = 0.0185 m/s²
Hence, the acceleration by train is 0.0185 m/s².