Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h-1 in 10 minutes.find its acceleration.​

Answer 1

Answer:

0.0185 m/s²

Explanation:

Given :

• Initial velocity of the train = u = 0 m/s

• Final velocity of the train = v = 40 km/h

• Time taken = t = 10 minutes = 600 seconds

To find :

• Acceleration of the train

Acceleration = (v-u) / t

v = 40×5/18 = 100/9 m/s

Acceleration = (100/9-0)/600

Acceleration = 100/9/600

Acceleration = 100/9×1/600

Acceleration = 1/54 m/s²

Acceleration = 0.0185 m/s²

The acceleration of the train is equal to 0.0185 m/s²

Answer 2

Answer:

Explanation:

Given :-

Initial velocity, u = 0 (As train starts from rest)

Final velocity, v = 40 km/h = 40 × 5/18 = 100/9 = 11.11 m/s

Time taken, t = 1 min = 10 × 60 = 600 seconds

To Find :-

Acceleration, a = ??

Formula to be used :-

1st equation of motion,

i.e, v = u + at

Solution :-

Putting all the values, we get

v = u + at

⇒ 11.11 = 0 + a × 600

⇒ a = 11.11 - 0/600

⇒ a = 11.11/600

⇒ a = 0.0185 m/s²

Hence, the acceleration by train is 0.0185 m/s² .