Question

A train starting from a railway station and moving with uniform acceleration attains a speed of 40m/s in 10s .find its acceleration.

Answer 1

Answer:

u=0 ,v= 40m\s,t=10s

Explanation:

by using 1 equation of motion

v=u+at

40=0+a^10

40=10a

a=40\10

a=4m\s2

Answer 2

Answer:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.

Final speed of the train, v = 40 km/h = \frac{5}{18}185 × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ a=\frac{v-u}{t}a=tv−u

Solution:-

Putting all the values, we get

⇒ a=\frac{v-u}{t}a=tv−u

⇒ a=\frac{11.11-0}{600}a=60011.11−0

⇒ a=\frac{11.11}{600}a=60011.11

⇒ a=0.0185 \: m/s^2a=0.0185m/s2

Hence, Acceleration of the train is 0.0185 m/s².

Explanation:

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