Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km/h in 10 minutes. Find its acceleration.​

Answer 1

Answer:

has

oz el la is hall

Explanation:

QC en ulla yo i has

Answer 2

$\textbf{ \huge\underline \red{ \underline{question} } : - }$

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km/h in 10 minutes. Find its acceleration.

$\textbf{\huge\underline{\underline\red{ solution} : - }} \\ \\ \\ \\ \mathfrak{ \: \underline\red{formula} : - } \: \: \: \: \huge{\: a \: = \frac{v - u}{t} } \\ \\ \underline{where} \\ \\ \textbf{ \: a = acceleration} \\ \\ \textbf{ \: v = final \: velocity} \\ \\ \textbf{ \: u = initial \: velocity} \\ \\ \textbf{ \: t \: = time } \\ \\ \textbf{ \red{ \: we \: know \: 1 \: min \: = \: 60 \: sec}} \\ \\ \textbf{ \purple{ \: hence}} \\ \\ \textbf{ \red{ \: 10 \: min \: = \: 10}} \: \times \textbf{ \red{ \:60 \: = \: 600 \: sec }} \\ \\ \textbf{ \purple { \:1 \: km \: = 1000 \: m \: and \: 1 \: hour \: = 3600min}} \\ \\ \textbf{ \: 40 km per hour } = \frac{40 \times 1000}{3600} = \frac{400}{36} = \frac{100}{9} = 11.11 \: m \: {sec}^{ - 1} \\ \\ \textbf{ \: v =} \: 11.11 \: m \: {sec}^{ - 1} \\ \\ \textbf{ \: u \: = 0 }\textbf{ \purple{(initial \: velocity \: is \: zero)} }\textbf{t = 600 } \\ \\ \\ \\ \textbf{\: a \: } = {\frac{v - u}{t} } = \frac{11.11 - 0}{600} = \frac{11.11}{600} = 0.018516667 \: m \: {sec}^{ - 2} \\ \\ \textbf{ \purple{hence \: acceleration \: is \: }} \purple{0.018516667 \: m \: {sec}^{ - 2}} \\ \\ \fbox{ \red{i \: hope \: it \: helps \: you.}}$