Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h–1 in 10 minutes. Find its acceleration.​
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Answer 1

Answer:

Answer:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.

Final speed of the train, v = 40 km/h = × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ a=v-u/t

Solution:-

Putting all the values, we get

⇒ a=v-u/t

⇒ a=11.11-0/600

⇒ a=11.11/600

⇒ a=0.0185 ms^2

Hence, Acceleration of the train is 0.0185 m/s².

Answer 2

↬ Given :-

• Initial velocity (u) = 0 m/s

• Final velocity (v) = 40 km/h

• Time (t) = 10 min

⸕ we can convert 40 km/h into m/s

• $\rm\:v=40\:km/h$

$\rm\longrightarrow\:v=40\times\:\dfrac{5}{18}$

$\rm\longrightarrow\:v=11.11\:m/s$

⸕ Now,we can convert 10 min into sec

• $\rm\:t=10\:min$

$\rm\longrightarrow\:t=10\times\:60$

$\rm\longrightarrow\:t=600\:sec$

↬ To Find :-

• Acceleration (a) = ?

↬ Solution :-

we know that,

$\orange{\bigstar}\:\:{\underline{\boxed{\bf\red{a=\dfrac{v-u}{t}}}}}$

$\rm\longrightarrow\:a=\dfrac{11.11-0}{600}$

$\rm\longrightarrow\:a=\dfrac{11.11}{600}$

$\rm\longrightarrow\:a=0.0185\:m/{s}^{2}$

Hence,the acceleration will be 0.0185 m/s²

➝ Acceleration :-It is defined as rate of change of velocity with respect to time.

• SI unit of acceleration is m/s².
• CGS unit of acceleration is cm/s².
• It is a vector quantity.
• It may be positive, negative and zero