Question

A train starting from a railway station and
moving with uniform acceleration attains a
speed of 40 km/h in 10 min. Find its
acceleration.
​

Answer 1

↦Solution : -

u = Initial Velocity = 0m/s

v = Final Velocity = 40km/h

a = Acceleration = ?

v = 40×5/18 = 200/18

[t = 10×60 = 600 seconds]

Now ,

a = (v-u)/t

a = (200/18-0)/600

a = 200×0/18×600 , a = 1/18×3

a = 1/84 m/s²

Answer 2

Hi there!

Your Answer :-

$\huge\bf\underline\red{\bigstar \: Given}$

Initial Velocity = 0m/s.

Time = 600s.

Final Velocity = 200/18s.

$\huge\bf\underline\red{\bigstar \: Solution}$

A = (V-U)/T.

A = (200/18-0)/600

A = 1/84ms²

So, Your Answer :- 1/84ms².