A train starting from a railway station and moving with inform acceleration, attains a speed of 40 kmh in 10 minutes, It's acceleration is : (A) 18.5 ms (B) 1.85 cm s (C) 18.5 cms (D) 1.85cm
Answers
Answered by
24
Answer:
(d) 1.85 cm/s²
Explanation:
Given :
Initial velocity = u = 0 m/s
Final velocity = v = 40 km/h = 40×5/18 = 100/9 m/s
Time = t = 10 minutes = 600 seconds
To find :
- Acceleration of the train
First equation of motion = V = u+at
100/9 = 0+a×600
100/9 = 600a
a = 100/9×1/600
a=1/54 m/s²
a = 0.0185 m/s² = 1.85 cm/s²
hence (d) is the correct option
Answered by
1
Answer:
(d) 1.85 cm/s²
Explanation:
Given :
Initial velocity = u = 0 m/s
Final velocity = v = 40 km/h = 40×5/18 = 100/9 m/s
Time = t = 10 minutes = 600 seconds
To find :
Acceleration of the train
First equation of motion = V = u+at
100/9 = 0+a×600
100/9 = 600a
a = 100/9×1/600
a=1/54 m/s²
a = 0.0185 m/s² = 1.85 cm/s²
hence (d) is the correct option
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