A train starting from a railway station and moving with uniform acceleration attains a speed 40km h^-1 in 10 minutes. Find its acceleration
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Answer:
- Acceleration of Train = 240 km h⁻²
Explanation:
Given:
- Train is starting from rest therefore, initial velocity of train, u = 0
- final velocity attained by train, v = 40 km h⁻¹
- Time taken for change in velocity, t = 10 min
To find:
- Acceleration of train, a =?
Formula required:
- First equation of motion
v = u + a t
[ Where v is final velocity, u is initial velocity, a is acceleration and t is time taken ]
Solution:
we have,
→ t = 10 min
→ t = 10/60 hrs
→ t = 1/6 hrs
Using first equation of motion
→ v = u + a t
→ 40 = ( 0 ) + a ( 1 / 6 )
→ 40 = a / 6
→ a = 40 × 6
→ a = 240 km h⁻²
Therefore,
- Acceleration of car is equal to 240 km h⁻².
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