Question

a train starting from a railway station and moving with uniform acceleration ,attains a speed of 40km/hr in 10 minutes. find acceleration
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Answer 1

Answer:

Explanation:

Answer 2

Answer :

$\large\bullet \: \boxed{\sf Acceleration \ of \ train = 0.0185\ m/s^{2}} \: \bullet$

$\large\underline{\underline{\frak{\qquad Given :\qquad}}}$

• Initial speed (u) = 0 km/hr = 0 m/s
• Final speed (v) = 40 km/hr
• Time taken (t) = 10 minutes

$\large\underline{\underline{\frak{\qquad To\:Find :\qquad}}}$

• Acceleration (a) of the train = ?

$\large\underline{\underline{\frak{\qquad Solution:\qquad}}}$

$\qquad \: \: \tiny \dag \: \: \underline{\textsf{First of all convert final speed from km/hr to m/s :}}$

$:\implies\sf 1 \: km/hr = \dfrac{5}{18} \: m/s$

$:\implies\sf 40 \: km/hr = \dfrac{5}{18} \: m/s$

$:\implies\sf Final \: speed \: (v) = 40 \times \dfrac{5}{18} \: m/s$

$:\implies\sf Final \: speed \: (v) = 20 \times \dfrac{5}{9} \: m/s$

$:\implies \underline{ \boxed{\sf Final \: speed \: (v) = 11.11\: m/s}}$

$\therefore\:\underline{\textsf{The Final speed (v) is \textbf{11.11 m/s}}}.$

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$\qquad \: \: \tiny \dag \: \: \underline{\textsf{From 1 ^{\text{st}} equation we get :}}$

$\dashrightarrow\:\: \bold{v = u + at}$

$\qquad \: \: \tiny \dag \: \: \underline{\textsf{Substituting \ value \ of \ v, \ u \ and \ t :}}$

$\sf\dashrightarrow\:\: 11.11 = 0 + a(10 \times 60)\:\:\Bigg\lgroup \because\: \textsf{\textbf{Converting the time from minutes to seconds}} \Bigg \rgroup$

$\sf \dashrightarrow 11.11 = a(600)$

$\sf \dashrightarrow a = \frac{11.11}{600}$

$\dashrightarrow \: \: \underline{ \boxed{ \sf a = 0.0185 \: m/s^2}}$

$\therefore\:\underline{\textsf{The Acceleration (a) of the train is \textbf{0.0185 m/s ^{\text 2} }}}.$

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